domingo, 20 de septiembre de 2009

4ª tarea de algebra 1-5

ENCONTRAR EL VALOR DE x

1.- (2)(-3)(5)+25x =(147/15)x-248/43-223/105
-30+25x=(147/15)x-248/42-223/105
-30+25x=9.8x-5.9-2.1
-30+34.8x=-5.9-2.1

34.8x=-5.9-2.1+30
34.8x=22
x=22/34.8
x=0.6

2.-(47/7)/(198/26)+28x=13+(14/67)(222/111)
1170/1386+28x=13+3108/1437
0.8+28x=13+2.1
28x=13+2.1-0.8
28x=14.3
x=14.3/28
x=0.5

3.-48/5 + (2/3)X = 1657 + 345
9.6+0.6x=1657+345
0.6x=1657+345-9.6
0.6x=2082.4

x=2082.4/0.6
x=3470.6

4.-(2)(-5)(-7)(-8)(9)+257896-1247-5x=951753+456
-5040+257896-1247-5x=951753+456
5x=951753+456+5040-257896+1247
5x=700600
x=700600/5
x=140120

5.-(5/3)+(4/3)=2x
9/3=2x
3=2x
3/2=x

1.5=X

6.-(6/7)(3/9)+3x=4-(17/5)
18/63+3x=4-(17/5)
0.2+3x=4-3.4
3x=4-3.4-0.2
3x=0.4
x=0.4/3
x=0.13

7.-(23/3)+(16/9)x=23x-12
7.6+1.7x=23x-12
7.6+24.7x=-12
24.7x=-12-7.6
24.7x=-19.6
x=-19.6/24.7
x=-0.7

8.-12x-18+(23/7)=(145/2)-4x
12x-18+3.2=72.5-4x
8x-18+3.2=72.5
8x=72.5+18-3.2
8x=87.3
x=87.3/8
x=10.9

9.-((14/2)(15/9)/(125/25))=17/3+(13/4)x
(210/18)/(125/25)=17/3+3.25x
5250/2250=17/3+3.25x
2.3=5.6+3.25x
2.3-5.6=3.25x
-3.3=3.25x
-3.3/3.25=x
-1.0=x

10.-22-178+33/5-16x=147+(248/16)x
22-178+6.6-16x=147+15.5x
22-178+6.6-0.5x=147
0.5x=147-22+178-6.6
0.5x=296.4
x=296.4/0.5
x=592.8

11.-951357-456258+(22/16)x=145x-654852+123987
951357-456258+1.3x=145x-654852+123987
951357-456258+146.3x-654852+123987
146.3x=-654852+123987-951357+456258
146.3x=-1025964
x=-1025964/146.3
x=-7012.74

1 comentario: